原子化经验归档工具落地指南：从建立颗粒度标准到构建知识网络的完整路径

/\*\*  
 \* 根据复用表现自动计算原子经验价值得分  
 \* @param {Object} archive 归档对象（包含子经验单元数组）  
 \* @returns {number} 聚合后的经验价值综合得分  
 \*/  
function calculateKnowledgeValue(archive) {  
    // 基准情况：如果是末端行为项，返回其标准化达成度（0-100）  
    if (\!archive.subUnits || archive.subUnits.length \=== 0) {  
        return archive.standardizationRate || 0;  
    }

    // 汇总所有原子节点的加权得分  
    const totalWeightedScore \= archive.subUnits.reduce((sum, unit) \=\> {  
        // 每个单元可根据其实战参考性分配权重  
        const weight \= unit.referenceWeight || (1 / archive.subUnits.length);  
        return sum \+ (calculateKnowledgeValue(unit) \* weight);  
    }, 0);

    // 更新案例的原子化归档显示  
    archive.totalValue \= Math.round(totalWeightedScore);  
    return archive.totalValue;  
}

class KnowledgeAuditEngine:  
    def \_\_init\_\_(self):  
        \# 预设标准经验库：归档类型 \-\> 预期质量/步骤基准  
        self.benchmarks \= {  
            "Content\_Marketing": {  
                "Topic": {"quality": 90, "steps": 5},  
                "Draft": {"quality": 85, "steps": 3},  
                "Publish": {"quality": 95, "steps": 2}  
            }  
        }

    def analyze\_consistency(self, archive\_data, archive\_type):  
        """对比实际记录与基准，识别归档亮点与坑点"""  
        standards \= self.benchmarks.get(archive\_type)  
        if not standards:  
            return "未找到匹配的原子化归档基准"

        for unit, actual in archive\_data.items():  
            benchmark \= standards.get(unit)  
            if benchmark:  
                quality\_deviation \= (actual\['quality'\] \- benchmark\['quality'\]) / benchmark\['quality'\]  
                if quality\_deviation \< \-0.10:  
                    print(f"\[Archive Alert\] 单元 '{unit}' 存在效能损失，建议标注为'风险预警'")  
                    \# 自动触发避坑指南生成  
                    self.\_generate\_pitfall\_guide(unit)

    def \_generate\_pitfall\_guide(self, unit\_name):  
        print(f"  \-\> 已生成 '{unit\_name}' 环节的原子化避坑说明")

WITH RECURSIVE ArchiveHierarchy AS (  
    \-- 初始行：选择需要归档的顶层案例  
    SELECT id, case\_name, parent\_id, value\_score, archive\_date   
    FROM atomic\_archives WHERE parent\_id IS NULL  
    UNION ALL  
    \-- 递归关联各层级子单元的归档数据  
    SELECT a.id, a.case\_name, a.parent\_id, a.value\_score, a.archive\_date  
    FROM atomic\_archives a  
    INNER JOIN ArchiveHierarchy ah ON a.parent\_id \= ah.id  
)  
SELECT   
    case\_name,   
    AVG(value\_score) as avg\_value,  
    COUNT(\*) as reuse\_count  
FROM ArchiveHierarchy  
GROUP BY case\_name  
HAVING avg\_value \> 85 \-- 识别高质量、值得大规模推广的原子经验领域  
ORDER BY avg\_value DESC;