std::logical_and
Defined in header <functional> | | |
|---|---|---|
template< class T > struct logical_and; | | (until C++14) |
template< class T = void > struct logical_and; | | (since C++14) |
函数对象,用于执行逻辑连接和%28逻辑连接%29。有效呼叫operator&&论类型T...
专门性
The standard library provides a specialization of std::logical_and when T is not specified, which leaves the parameter types and return type to be deduced. logical_and<void> function object implementing x && y deducing argument and return types (class template specialization) | logical_and<void> | function object implementing x && y deducing argument and return types (class template specialization) | (since C++14) |
|---|---|---|---|
logical_and<void> | function object implementing x && y deducing argument and return types (class template specialization) |
成员类型
Type | Definition |
|---|---|
result_type(deprecated in C++17) | bool |
first_argument_type(deprecated in C++17) | T |
second_argument_type(deprecated in C++17) | T |
成员函数
operator() | returns the logical AND of the two arguments (public member function) |
|---|
STD::逻辑[医]操作员%28%29
bool operator()( const T& lhs, const T& rhs ) const; | | (until C++14) |
|---|---|---|
constexpr bool operator()( const T& lhs, const T& rhs ) const; | | (since C++14) |
返回逻辑和lhs和rhs...
参数
lhs, rhs | - | values to compute logical AND of |
|---|
返回值
结果lhs && rhs...
例外
%280%29
可能的实施
ConstT&rhs%29 const{返回lhs&rhs;}
*。
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