std::allocator::deallocate
void deallocate( T* p, std::size_t n ); | | |
|---|
分配指针引用的存储。p，它必须是以前调用的指针。allocate()...
争论n必须等于调用allocate()原产p否则，行为就没有定义。
打电话::operator delete(void*)，但未具体说明何时和如何调用它。
参数
p | - | pointer obtained from allocate() |
|---|---|---|
n | - | number of objects earlier passed to allocate() |
返回值
%280%29
另见
allocate | allocates uninitialized storage (public member function) |
|---|---|
deallocate static | deallocates storage using the allocator (public static member function of std::allocator_traits) |
© cppreference.com在CreativeCommonsAttribution下授权-ShareAlike未移植许可v3.0。
本文档系腾讯云开发者社区成员共同维护，如有问题请联系 cloudcommunity@tencent.com
