= null and userType !...= null and item.userType !...= null and userType !...(@Param("mobile") String mobile,@Param("userType") String userType); 如果参数类型是数值型。...= null and userType !
看到很多公共的部分很多，局部不同可以考虑用模板方法模式 实例 public class CourseRelationService { public void byCourse(String userType...,String CourseID,double CoursePrice){ double price=0; if("monthvip".equals(userType))...{ price=CoursePrice*1.0; } if("yearvip".equals(userType)){ price...=CoursePrice*0.75; } if("svip".equals(userType)){ price=CoursePrice*0.5;...,String CourseID,double CoursePrice){ double price=0; if("monthvip".equals(userType))
/default.html"); exit; } DBConn(); $password=md5($password); $SQL = "Select UserName,UserType..."); $_SESSION["usertype"]=$Rs['UserType']; $_SESSION["username"]=$username; //echo $_SESSION...["username"]; if ($_SESSION["usertype"]==1){ Go_Msg("登陆成功！"...,"default.php"); //header('Location:http://163.com'); } if ($_SESSION["usertype"]==2){.../user2/default_1.php"); } if ($_SESSION["usertype"]==3){ Go_Msg("登陆成功！","..
例如：性别：Man（男）、Woman（女）订单状态：Nonpayment（未付款）、Paid（已付款）、Delivered（已发货）、Checked（已确认收货）定义枚举类型public enum UserType...对象的属性 private String typeName; private Integer typeId; // 3.私有化构造器(private 可省略) private UserType...public static void main(String[] args) {// [common, sectionAdmin, superAdmin] UserType[] userTypes...= UserType.values(); // 返回具有指定名称的枚举常量 UserType common = UserType.valueOf("common"); // 返回具有指定名称的指定枚举类型的枚举常量...UserType common1 = Enum.valueOf(UserType.class, "common"); // 返回枚举常量的名称 (Enum 类重写了 toString()
// 举个例子：一个网站有用户系统、商家系统、网站后台3个系统 //可以分3个userType, user ,shop , system //网站后台一般都有角色，如admin,employee...代码如下： 代码： namespace MVCCommonAuth { #region 功能说明 // 举个例子：一个网站有用户系统、商家系统、网站后台3个系统 //可以分3个userType...shop,admin,employee,但是admin和employee在一个客户端是不能同时登陆的，所以他们是同一类用户（system） #endregion public enum UserType...) { var keyName = CookieNamePrefix + userType; if (!...) { var user = GetUser(userType); if (user !
1 2 3 4 5 6 7 #先获取组的对象 usertype = models.UserType.objects.fiter(id=2) #添加的时候直接添加对象就可以 models.UserInfo.objects.create...1 models.UserType.objects.get(id=1) ?...1 2 3 4 5 6 7 8 9 10 11 obj=models.UserType.objects.get(id=1) obj.caption====得到在UserType表中id为1对应的...age", "app01_usertype"."id", "app01_usertype"."...user_type_id" = "app01_usertype"."id") 所以说select_related就是优化查询的！
()) { System.out.println("白银会员 优惠50元"); result = money - 50; } elseif (type == UserType.GOLD_VIP.getCode...()) { result = new SilverStrategy().compute(money); } elseif (type == UserType.GOLD_VIP.getCode...()) { result = new GoldStrategy().compute(money); } elseif (type == UserType.PLATINUM_VIP.getCode...()) { strategy = new SilverStrategy(); } elseif (type == UserType.GOLD_VIP.getCode()) {...strategy = new GoldStrategy(); } elseif (type == UserType.PLATINUM_VIP.getCode()) { strategy
= null and userType !...> testIfSql(@Param("mobile") String mobile,@Param("userType") String userType); @Select({...= null and item.userType !...= null and item.userType !...; } public void setUserType(String userType) { this.userType = userType; }
:不解析条件,不报错,都走 包含网关:解析条件,条件成立就走,不成立就不走,全都不成立报错 需求: 体检流程 如果是领导 就走 常规,抽血,VIP,普通员工只走常规,抽血 使用流程变量控制 领导:userType...=2 员工:userType=1 image.png package com.itheima.test.testGateWay; import org.activiti.engine.*; import...RuntimeService runtimeService = defaultProcessEngine.getRuntimeService(); Integer userType...= 1; Map map = new HashMap(); map.put("userType",userType);...=1 领取->常规->抽血->早餐->结束 userType=2 领取->常规->抽血->早餐->VIP->结束 作者：彼岸舞 时间：2020\09\08 内容关于：Activiti工作流 本文来源于网络
models/user.go type UserType int const ( ApplicationAdminType UserType = iota SuperAdminType...= nil || userType == models.UnAuthorizedUserType { log.Println(err) ctx.Output.JSON(map..., false, false) return } ctx.Input.SetData("UserType", userType) ctx.Input.SetData...UserType, err error) { userType = UnAuthorizedUserType //判断是否过期 if int64(*retrospecTokenResult.Exp...= ApplicationAdminType } } return userType, err } 维护client的JWT Token的任务，我直接写到获取用户角色这里了
> userType = ClassUtils.getUserClass(handlerType); //解析类并且获取所有带有requestMapping的方法 Map methods = MethodIntrospector.selectMethods(userType, (MethodIntrospector.MetadataLookup...) method -> { try { return getMappingForMethod(method, userType); } catch..." + method, ex); } }); if (logger.isTraceEnabled()) { logger.trace(formatMappings(userType...methods.forEach((method, mapping) -> { Method invocableMethod = AopUtils.selectInvocableMethod(method, userType
，后面用得着， 用户类： @Data public class User { private Integer id; private String name; private UserType...userType = UserType.COMMON; @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss") private LocalDateTime...registerTime; } 用户类型枚举类： @Getter @JsonFormat(shape = JsonFormat.Shape.OBJECT) public enum UserType {...VIP("VIP用户"), COMMON("普通用户"); private String code; private String type; UserType...思前想后，看文章开始定义的User和UserType类，标记数据序列化格式@JsonFormat，再突然想起之前看到过的一些文章，SpringMVC底层默认是使用Jackson进行序列化的，那好了，就用
}; void setTextSuccess(); void setText(QString text, QString time, QSize allSize, User_Type userType...() { return m_userType;} protected: void paintEvent(QPaintEvent *event); private: QString...m_msg; QString m_time; QString m_curTime; QSize m_allSize; User_Type m_userType = User_System...) { m_msg = text; m_userType = userType; m_time = time; m_curTime = QDateTime::fromTime_t...(time.toInt()).toString("hh:mm"); m_allSize = allSize; if(userType == User_Me) {
localStorage.setItem('token',res.data.token); localStorage.setItem('userType...',res.data.userType); self....}) 登录逻辑，当成功之后跳转到首页，但是后台返回200登录成功，却走了catch语句，这里唯一可能的原因： 传入参数正确，所以可以正确返回，但是成功之后的语句有语法错误或者 res.data.userType
= findTaskType(userid); logger.info("准备查询userType为{}的任务", userType); List tasks = taskService.createTaskQuery...().taskName(userType).orderByTaskCreateTime().asc().list(); List utasks = new ArrayList...= appUser.getUserType(); if (userType == null) return null; if (!...StringUtils.isEmpty(userType)) { if ("2001".equals(userType)) { return "CustomerServiceApproval...; } public void setUserType(String userType) { this.userType = userType; } public String getIdentifyTable
中执行如下配置 from django.contrib import admin from app01 import models admin.site.register(models.UserType...models.UserInfo) admin.site.register(models.UserGroup) admin.site.register(models.Asset) 2·设置数据表名称 class UserType...verbose_name = '用户类型' verbose_name_plural = '用户类型' 3·打开表之后,设定默认显示,需要早model中作如下配置 class UserType...username', 'password', 'email') search_fields = ('username', 'email') admin.site.register(models.UserType...username', 'email') list_filter = ('username', 'email') admin.site.register(models.UserType
String username; private String password; private String email; private Integer usertype...this.username = username; this.password = password; this.email = email; this.usertype...= usertype; this.lastlog = lastlog; } @Override public String toString() {...=" + usertype + ", lastlog=" + lastlog + '}'; } public Integer...; } public void setUsertype(Integer usertype) { this.usertype = usertype; }
= null and userType !...(@Param("mobile") String mobile,@Param("userType") String userType); @Select({ "", "SELECT...= null and item.userType !...= null and item.userType !...; } public void setUserType(String userType) { this.userType = userType; } public String getIdentifyTable
为此，我们需要一个实现org.hibernate.usertype.UserType接口的类，来实现两个世界的数据转换/映射工作。...Hibernate的自定义类型(UserType) UserType是Hibernate提供的一个自定义数据类型的接口。...所有自定义数据均需实现此接口，或者从org.hibernate.usertype中定义的接口中选择一个合适的接口。 鉴于我们的场景比较简单，直接实现UserType即可满足需求。...org.hibernate.HibernateException; import org.hibernate.engine.spi.SharedSessionContractImplementor; import org.hibernate.usertype.UserType...how-to-map-the-type-interval-in-hibernate/6139581#6139581 * * @version 1.0 * @since 1.0 */ public class IntervalType implements UserType
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