php mysql根据结果显示表格标记

<?php
// 连接数据库
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database_name";

$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 查询数据
$sql = "SELECT id, name, status FROM your_table";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    echo "<table border='1'><tr><th>ID</th><th>Name</th><th>Status</th></tr>";
    while($row = $result->fetch_assoc()) {
        // 根据状态标记颜色
        $statusColor = ($row["status"] == 'active') ? 'green' : 'red';
        echo "<tr><td>" . $row["id"]. "</td><td>" . $row["name"]. "</td><td style='color:".$statusColor."'>" . $row["status"]. "</td></tr>";
    }
    echo "</table>";
} else {
    echo "0 结果";
}
$conn->close();
?>