我有下面的代码来显示数字如果记录在表中,它总是显示1,即使我将列名更改为另一个列名;
$con = @mysqli_connect( "localhost:3306", "root", "P@ssw0rd", "classicmodels" ) or die ("Couldn't//get total number of records
我使用下面的php在db搜索中显示返回的的记录数。$sql = "SELECT COUNT(id) FROM authorsbooks WHERE author LIKE '%$searchquery%'";$row = mysqli_fetch_row($query);$textline1 = "Your Search Returned (<但是,我无法显
dataGranpremio) as anno GROUP BY YEAR (dataGranpremio)"; die ("Errore nella query " . mysqli_error($db_connection)); $numero = mysqli_num_rowsphp while ($ris=mys