我需要从一个表中提取3个值,并将每个值赋值给一个变量,每个值基于列、类型和id。$ht_live_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='L'");$htCODE_Live = $ht_live_result['htcode'];
您
嗨,我写了这个MySQL存储的proc,我一直收到这个语法错误。#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server@start = 1505469600;;;
我将DELIMITER ;;添加到脚本的顶部,因为在设置变量时一直有语法错误
read -p "Set the password for the database [min. 4 characters]: " MPASS
path/to/setup-mysql.shmysql-community-server/data-dir select ''"
debconf-set-selections <<< "mysql-community-server m