我正在为系统的自动安装和配置编写bash脚本,我需要能够从脚本中声明的变量中为mysql设置根密码,但我无法让它工作。
read -p "Password `echo $'\n> '`" mysql_passwd
mysql --defaults-file=/etc/mysql/debian.cnf mysql -Bse 'UPDATE user SET password=PASSWORD("$mysql_passwd") WHERE User="root";flush privileges;'
当在没有变
之前已经创建了表,并且已经插入了数据
似乎无法执行insert命令,此阶段尚未尝试其他命令
已重置mysql,是否仍有...
Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 1
Server version: 5.6.20 MySQL Community Server (GPL)
Copyright (c) 2000, 2014, Oracle and/or its affiliates. All rights reserved.
Oracle is a regist
我试图使用以下命令从ssh创建mysql用户:
sshpass -p "PASSWORD" ssh -t -o StrictHostKeyChecking=no USER@IP "echo "CREATE USER 'NAME'@'localhost' IDENTIFIED BY 'MDP'" | mysql"
但这不起作用
ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual tha
前几天,我在一些遗留代码中遇到了一个SQL注入的机会.
// input: email@email.com"
$email = $_POST['email'];
mysql_query('SELECT * FROM users WHERE email = "'.$email.'" ');
// output: you have an error in your syntax near " ...
// input: email@email.com'
mysql_query("SELECT * FR
我正在尝试将HTML代码插入到MySQL数据库的字段中。
我使用以下代码来完成这项工作
cur.execute("INSERT INTO `table1`(field1) VALUES("+ str(data) +")")
但我得到以下错误:
_mysql_exceptions.ProgrammingError: (1064, 'You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the righ
对于下面的python/ mysql查询
op = dbcon.query("select * from configtable where xmlfile like '%"Check_This_Attribute" enabled="true"%'")
获取错误:
SyntaxError:无效语法
有谁能帮忙吗?
因此,我在Ruby/Sinatra中构建了一个登录/注册页面,并尝试添加一些逻辑,以便如果有人尝试使用正在使用的电子邮件进行注册,它会告诉他们,而不允许他们注册
require 'rubygems'
require 'sinatra'
require 'mysql'
get "/" do
erb :form
end
post "/" do
begin
con = Mysql.new('localhost', 'tut', 'tut'
我正在尝试重新创建一个案例选择,我成功地在续集Pro中实现了;所有这些都利用了MySQL。
以下是我的SQL查询:
SELECT company_db.location.id AS "Id",
company_db.location.name AS "Name",
CASE WHEN company_db.location.id = 8 THEN "NY"
WHEN company_db.location.id = 37 THEN "ATL"
ELSE NULL END AS
我的Powershell脚本包含以下查询-
# This code defines the search string in the database table
$SQLQuery = "SELECT bug_id,
bug_status,
resolution,
short_desc,
DATE_FORMAT(deadline, "%m/%d/%Y")
FROM bugs
WHERE ( bug_status IN ( 'RESOLVED', 'VERIFIED'
我有一个PHP程序,它可以插入一个新行,或者更新现有行(如果它已经存在)。在浏览器上运行时,它会返回错误。
但是,实际的调用在phpMySQL上运行正常-没有报告错误,行被更新。
"Errormessage: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"updated", `conditions` =" ",'
我知道这个错误:
SyntaxError: EOL while scanning string literal
在尝试将超过2000万行的CSV文件推送到MySQL服务器时,使用以下python代码:
cur = connection.cursor()
query = "LOAD DATA LOCAL INFILE 'path to csv file' INTO TABLE table.name FIELDS OPTIONALLY ENCLOSED BY '"' LINES TERMINATED BY '\r\n';"
我在PHP中运行以下命令有困难:
$con = mysql_connect("host", "username", "password") or die ("Unable to connect to server");
mysql_select_db("database") or die ("Unable to select database");
$sql = "UPDATE `table` SET `column` = TRIM(BOTH '"' FROM `co
我正在写一个网址缩写...我有一个错误,我似乎就是无法摆脱。我觉得这很明显,但我没有看到它。
(我是菜鸟;) )错误如下:
'mysql_result(): supplied argument is not a valid MySQL result resource in <b>/home2/bythewa1/public_html/jbgc/func.inc.php</b> on line <b>23'
这是我在该页面上的代码。
<?php
include("db.inc.php");
function is_min