我正在创建Django的Model类的子类,并要求用户实现一些属性和方法。AbstractFooMeta(ModelBase, ABCMeta):
class AbstractFoo(ABC, models.Modelmichael/.venv/project/lib/python3.9/site-packages/django/d
php
use FOS\UserBundle\Model\UserManager;
class CustomUserManager extends UserManager implementsmethods and must therefore be declared abstract or implement the rem