如果缓存命中率为95%,主存命中率(缓存未命中后)为99%,则访问一个字的平均时间是多少?Here is how I solved it.95 cache hits(due to 0.95 cache hit ratio)memory access time
=cache hit ratio * cache access time + (1 - hit ratio) * miss penalty(o
如果100%的缓冲和过程缓存命中率被认为是不好的一般?我用下面的查询检查缓冲区缓存命中率,显示100% (100.0000000000000) FROM sys.dm_os_performance_counters
WHERE counter_name = 'Buffer cacheOBJECT_NAME =