我正在尝试使用@nguniversal/express-engine,我已经安装并尝试运行它,但它在main.js文件中给出错误。
这就是我得到的错误
C:\Folder\ssr\dist\ssr\server\main.js:179450
})(window, function() {
^
ReferenceError: window is not defined
at Object.rdXg (C:\Folder\ssr\dist\ssr\server\main.js:179450:4)
at __webpack_require__ (C:\Folder\s
我有HABTM协会
我的模特
class Ssr < ActiveRecord::Base
has_and_belongs_to_many :ssr_groups
validates :ssr_groups, presence: true
end
class SsrGroup < ActiveRecord::Base
has_and_belongs_to_many :ssrs, dependent: :destroy
validates :name, presence: true
end
我的工厂
FactoryGirl.define do
f
我正在运行一个使用"@ckeditor/ckeditor5-angular": "1.2.3"和自定义的应用程序。我添加了SSR (服务器端渲染- Angular Universal)支持:
ng add @nguniversal/express-engine
当我运行npm run dev:ssr时,我得到了以下错误:
ReferenceError: window is not defined
at Object../node_modules/@ckeditor/ckeditor5-build-classic/build/ckeditor.
我有一些JS代码,大致如下所示: let ssr = async (arg) => arg || "hello js";
export {ssr as default}; 我想从Java访问和调用ssr。 我该怎么做呢? 我一直在尝试这样的东西: var ctx = Context.newBuilder("js")
.allowIO(true)
.allowHostAccess(HostAccess.ALL)
.build();
var ss
我有一个关于在sql的select语句中重用以下代码的问题。我想知道是否可以为这个语句声明一个变量
CASE
WHEN ssr.rating = 'A' OR ssr.rating LIKE 'A[+-]'
THEN 1
WHEN ssr.rating = 'AA' OR ssr.rating LIKE 'AA[+-]'
THEN 2
WHEN ssr.rating = 'BBB' OR ssr.rating LIKE 'BBB[+-]'
THEN
你好,谁能告诉我包含子网格值的本地数据的json格式。我使用了以下格式,但是子网格数据没有加载到子网格表格中。
var data=[{"Left_ssr_id":CaGM33098,"Mismatches":"6","Gaps":"1","AlignLen":"1119","Identity":"99.37","right_ssr_start":17308507,"Qstart":"33","qu
错误:
错误:您必须通过NgModule或NgModuleFactory才能在View.engine (C:\ssr\dist\server.js:39238:23) at View.render (C:\ssr\dist\server.js:123884:8) at tryRender (C:\ssr\dist\server.js:121592:10) at Function.render (C:\ssr\dist\server.js:121544:3) at ServerResponse.render (C:\ssr\dist\server.js:130425:7 )进行引导。C:\ss
我正在尝试提取跨越多行的内容。内容看起来像这样:
some content here
[1/1/2015 - SSR] something
[1/2/2015 - SSR] another:
*something here
*another something here
not relevant, should not be returned
[1/3/2015 - SSR] another one
*前总是有一个空格
我使用的代码是:
re.search(r'.*- SSR](.*)',line,re.DOTALL)
预期输出为:
[1/1/2015 - SSR] som
我在group by栏目评分上遇到了问题。当我执行它时,它会给出“无效的列名'rate'”。
有人能帮我吗?谢谢!!
SELECT
......
CASE
WHEN level_1 = 'Corporate'
THEN
CASE
WHEN ssr.rating = 'A' OR ssr.rating LIKE 'A[+-]'
THEN 'Corp A'
WHEN s
我通过sql执行此操作,但我希望在hql中执行此操作,在from ( select count(*)...)中使用select语句。在hql中不起作用,任何建议和优化都将不胜感激。
SELECT u.username,u.device_tocken,sr.count
from users u,
(select count(*) as count ,ssr.recepient as res from survey_recipient ssr where
(ssr.is_read is false and ssr.recepient in ('abc',