js 两个array去重复

function removeDuplicates(arr1, arr2) {
  const combined = [...arr1, ...arr2];
  return [...new Set(combined)];
}

const array1 = [1, 2, 3, 4];
const array2 = [3, 4, 5, 6];
console.log(removeDuplicates(array1, array2)); // 输出: [1, 2, 3, 4, 5, 6]

function removeDuplicates(arr1, arr2) {
  const combined = arr1.concat(arr2);
  return combined.filter((item, index) => combined.indexOf(item) === index);
}

const array1 = [1, 2, 3, 4];
const array2 = [3, 4, 5, 6];
console.log(removeDuplicates(array1, array2)); // 输出: [1, 2, 3, 4, 5, 6]

function removeDuplicates(arr1, arr2) {
  const combined = arr1.concat(arr2);
  return combined.reduce((unique, item) => {
    return unique.includes(item) ? unique : [...unique, item];
  }, []);
}

const array1 = [1, 2, 3, 4];
const array2 = [3, 4, 5, 6];
console.log(removeDuplicates(array1, array2)); // 输出: [1, 2, 3, 4, 5, 6]

function removeDuplicates(arr1, arr2) {
  const map = new Map();
  const combined = arr1.concat(arr2);
  combined.forEach(item => map.set(item, true));
  return Array.from(map.keys());
}

const array1 = [1, 2, 3, 4];
const array2 = [3, 4, 5, 6];
console.log(removeDuplicates(array1, array2)); // 输出: [1, 2, 3, 4, 5, 6]

function removeDuplicatesByProperty(arr, prop) {
  const map = new Map();
  return arr.filter(item => !map.has(item[prop]) && map.set(item[prop], true));
}

const array = [{id: 1, name: 'Alice'}, {id: 2, name: 'Bob'}, {id: 1, name: 'Alice'}];
console.log(removeDuplicatesByProperty(array, 'id')); // 输出: [{id: 1, name: 'Alice'}, {id: 2, name: 'Bob'}]