WITH 1 INCREMENT BY 1), NAME VARCHAR2(50),); 连接字符串起作用> 以前,我使用的是MySQL,它很有效,但我不知道如何在Oracle中实现同样的结果 #PHP: MySQL Database Connection (db.php):
#PHP+MySQL: INSERT new user (userControlle
我有一个MySQL查询,它在phpmyadmin中执行时返回正确的结果,但是,有谁知道我如何使这个查询更加简化(更简单),以及如何在PHP循环中将$trackNumber变量附加到$info['trackName$data = mysql_query(" SELECT ( SELECT FROM league ll.leagueID = 1
FROM le
php $pickstory=$_POST['pickstory']; WHERE story = '$pickstory'", $conexion);
if($fila= mysql_fetch_rowphp while ($fila= mysql_fetch_row($result)) { ?>
$connect = mysql_connect("localhost", "username", "password"); mysql_selectdb('phplogin');
$query = mysql_query("SELECT * FROM forum ORDER BY time desc");$query2 = mysql_query