我已经创建了一个包含两个连接表的查询,并希望返回一列中的中位数作为结果。查询如下所示:
select table1.column1, count(distinct(table2.column2)) from table1 left join table2 on table1在这个查询中,有没有办法在不做重大修改的情况下做到这一点?
希望获得关于以下最佳方法的建议 TBL1 (本地SQL DB),其中ID = varchar TBL2 (远程MYSQL DB) where ID = INT WITH TBL1 as (FROM [DB]FROM TBL1 Left Outer join TB2 ON TBL1.ID = TBL2.I
我有一个超过10,000行的大表,不久的将来它将增长到1,000,000,并且我需要运行一个查询,为每个用户返回每个关键字的时间值。我现在有一个,它非常慢,因为我使用左连接,它需要一个子查询/关键字:rawdata left join
(SELECT user, sec_to_time(SuM(time_to_sec(EndTime-StartTime))) as 'Fac
FROM (SELECT p1.name AS name1, p2.name AS name2 FROM friend f INNER JOINperson p1 ON f.person_id = p1.id INNER JOIN person p2 ON f.friend_id = p2.id WHERE p2.name LIKE 'GinaUNION ALL (SELECT p1.name AS name1, p2.name
下面是我的代码: select NAME from EMPLOYEES inner join SALES on EMPLOYEES.NO_EMPLOYEES = SALE.NO_EMPLOYEES
unionselect COMPANY from SALES inner join CLIENTS on SALES.CODE_CLIENT = CLIENTS.CODE_CLIENT where CLIENTS.CITY
我正在尝试显示一个显示课程列表的表格。我想加入一个栏目,显示已完成课程的人数,如果可能,也显示尚未完成课程的人数。Coursescourseid | studentid | some other fields | has_completedCourse Title | some other fields | Students completed | Students not completed
Something etc