我有一个表,上面有(order_id,时间戳)。时间戳表示订单的交付日期,该日期可能在将来发生。如何使用一条select语句获得现在的最后5个订单和接下来的5个订单?有没有可能在不使用联合查询的情况下在sql中做到这一点?类似这样的东西,但没有联合:order by timestamp desc limit5
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1.Completed_order,2.viewed_page,3.email。我编写的查询是 activity_id, ts, customer,activity, when activity = 'email='email' end as cndn
from activity_stream as az1 wherec
我有一个在PostgreSQL中运行的SQL查询,它看起来就像这样:(如果ActiveRecord没有尽可能地优化,我深表歉意) CASE WHENeducations.cards_done - items.marker)) THEN 0 INNER JOIN educations ON educations.item_id
where date <= %s order by date LIMIT (select count(*) from contest where date <= %s) - 1) as new WHERE"
LINE 1: select row_number from (select row_number() over(order by d...select row_number from (<
在CentOS 7.6服务器(IntelCorei7-6700,64 GB DDR4 RAM,RAID1 SSD)上,我使用以下Linux包运行了一个用PL/pgSQL和Javafor移动和桌面文字游戏编写的后端:保镖-1.9.0-1.rhel7.x86_64
postgresql-jdbc-42.2.5-1.rhel7* from words_geoip order by random