Memcpy C++替代方案

#include <algorithm>

int main() {
    int source[5] = {1, 2, 3, 4, 5};
    int destination[5];

    std::copy(std::begin(source), std::end(source), std::begin(destination));

    // destination 现在包含 source 的内容
    return 0;
}

#include <cstring>

template<typename T>
void safe_memcpy(T* dest, const T* src, size_t count) {
    static_assert(std::is_trivially_copyable<T>::value, "Type must be trivially copyable");
    std::memcpy(dest, src, count * sizeof(T));
}

int main() {
    int source[5] = {1, 2, 3, 4, 5};
    int destination[5];

    safe_memcpy(destination, source, 5);

    // destination 现在包含 source 的内容
    return 0;
}