Matplotlib绘制比例三角形

import matplotlib.pyplot as plt

# 定义三个变量的比例关系
var1 = 0.4
var2 = 0.3
var3 = 0.3

# 创建一个等边三角形的坐标点
triangle = [(0, 0), (1, 0), (0.5, 0.866)]

# 计算各个变量在三角形中的坐标点
point1 = (var1 * triangle[0][0] + var2 * triangle[1][0] + var3 * triangle[2][0],
          var1 * triangle[0][1] + var2 * triangle[1][1] + var3 * triangle[2][1])
point2 = (var2 * triangle[0][0] + var3 * triangle[1][0] + var1 * triangle[2][0],
          var2 * triangle[0][1] + var3 * triangle[1][1] + var1 * triangle[2][1])
point3 = (var3 * triangle[0][0] + var1 * triangle[1][0] + var2 * triangle[2][0],
          var3 * triangle[0][1] + var1 * triangle[1][1] + var2 * triangle[2][1])

# 绘制比例三角形
plt.figure(figsize=(5, 5))
plt.plot([triangle[0][0], triangle[1][0], triangle[2][0], triangle[0][0]],
         [triangle[0][1], triangle[1][1], triangle[2][1], triangle[0][1]], 'k-')
plt.plot([triangle[0][0], point1[0]], [triangle[0][1], point1[1]], 'r--')
plt.plot([triangle[1][0], point2[0]], [triangle[1][1], point2[1]], 'g--')
plt.plot([triangle[2][0], point3[0]], [triangle[2][1], point3[1]], 'b--')
plt.plot(point1[0], point1[1], 'ro')
plt.plot(point2[0], point2[1], 'go')
plt.plot(point3[0], point3[1], 'bo')
plt.text(triangle[0][0], triangle[0][1], 'Var1', ha='right', va='top')
plt.text(triangle[1][0], triangle[1][1], 'Var2', ha='left', va='top')
plt.text(triangle[2][0], triangle[2][1], 'Var3', ha='center', va='bottom')
plt.xlim(-0.1, 1.1)
plt.ylim(-0.1, 1.1)
plt.axis('off')
plt.show()