C#尝试拆分字符串以获取json对象值

using Newtonsoft.Json.Linq;

string jsonString = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

// 解析JSON字符串
JObject jsonObject = JObject.Parse(jsonString);

// 获取name字段的值
string name = (string)jsonObject["name"];
Console.WriteLine("Name: " + name);

// 获取age字段的值
int age = (int)jsonObject["age"];
Console.WriteLine("Age: " + age);

// 获取city字段的值
string city = (string)jsonObject["city"];
Console.WriteLine("City: " + city);

string street = (string)jsonObject["address"]["street"];
string zipcode = (string)jsonObject["address"]["zipcode"];