获取嵌套字典中的键，并将其与递归Python 3的路径相关联

def get_key_paths(nested_dict, path=''):
    key_paths = []
    
    for key, value in nested_dict.items():
        new_path = f'{path}/{key}' if path else key
        
        if isinstance(value, dict):
            key_paths.extend(get_key_paths(value, new_path))
        else:
            key_paths.append(new_path)
    
    return key_paths

nested_dict = {
    'a': {
        'b': {
            'c': 1,
            'd': 2
        },
        'e': 3
    },
    'f': {
        'g': {
            'h': 4
        }
    }
}

key_paths = get_key_paths(nested_dict)
print(key_paths)

['a/b/c', 'a/b/d', 'a/e', 'f/g/h']