统计每个字典键中包含一个值的值的个数

def count_values(dictionary):
    count = {}
    for key, value in dictionary.items():
        if value is not None:
            if key in count:
                count[key] += 1
            else:
                count[key] = 1
    return count

my_dict = {'a': 1, 'b': None, 'c': 3, 'd': None, 'e': 5}

{'a': 1, 'c': 1, 'e': 1}