用C语言打印链表的第一个元素

struct Node {
    int data;
    struct Node* next;
};

struct Node* createLinkedList() {
    struct Node* head = NULL;
    struct Node* second = NULL;
    struct Node* third = NULL;

    // 分配内存并设置节点的值
    head = (struct Node*)malloc(sizeof(struct Node));
    second = (struct Node*)malloc(sizeof(struct Node));
    third = (struct Node*)malloc(sizeof(struct Node));

    head->data = 1;
    head->next = second;

    second->data = 2;
    second->next = third;

    third->data = 3;
    third->next = NULL;

    return head;
}

void printFirstElement(struct Node* head) {
    if (head != NULL) {
        printf("第一个元素的值为：%d\n", head->data);
    } else {
        printf("链表为空。\n");
    }
}

int main() {
    struct Node* head = createLinkedList();
    printFirstElement(head);
    return 0;
}