如何通过在Powershell中单击GUI形式的按钮来返回特定的错误级别？

Add-Type -AssemblyName System.Windows.Forms

# 创建窗体
$form = New-Object System.Windows.Forms.Form
$form.Text = "错误级别选择"
$form.Size = New-Object System.Drawing.Size(300, 200)
$form.StartPosition = "CenterScreen"

# 创建按钮
$button = New-Object System.Windows.Forms.Button
$button.Location = New-Object System.Drawing.Point(100, 50)
$button.Size = New-Object System.Drawing.Size(100, 30)
$button.Text = "返回错误级别"
$button.Add_Click({
    # 在按钮点击事件中返回特定的错误级别
    $form.DialogResult = [System.Windows.Forms.DialogResult]::OK
    $form.Close()
})
$form.Controls.Add($button)

# 显示窗体
$result = $form.ShowDialog()

# 根据返回的结果进行相应处理
if ($result -eq [System.Windows.Forms.DialogResult]::OK) {
    # 返回特定的错误级别
    Write-Error "这是一个错误信息" -ErrorAction Stop
} else {
    # 其他处理逻辑
}