如何递增URL字符串中特定参数的数字部分？

import re

def increment_url_param(url, param_name):
    # 解析URL字符串，获取参数部分
    url_parts = url.split('?')
    base_url = url_parts[0]
    params = url_parts[1] if len(url_parts) > 1 else ''

    # 提取特定参数的数字部分
    pattern = r'(^|&){0}=([^&]*)'.format(param_name)
    match = re.search(pattern, params)
    if match:
        param_value = match.group(2)
        try:
            # 将数字部分进行递增操作
            incremented_value = str(int(param_value) + 1)
            # 替换回原始URL字符串中的参数部分
            params = re.sub(pattern, r'\1{0}={1}'.format(param_name, incremented_value), params)
        except ValueError:
            # 数字部分无法转换为整数，不进行递增操作
            pass

    # 重新构建URL字符串
    incremented_url = base_url + '?' + params
    return incremented_url

# 示例用法
url = 'https://www.example.com/page?param1=value1&param2=123&param3=abc'
param_name = 'param2'
incremented_url = increment_url_param(url, param_name)
print(incremented_url)