如何获取多个同名key的JSON值

import json

def get_values(obj, key):
    values = []
    if isinstance(obj, dict):
        for k, v in obj.items():
            if k == key:
                values.append(v)
            elif isinstance(v, (dict, list)):
                values.extend(get_values(v, key))
    elif isinstance(obj, list):
        for item in obj:
            values.extend(get_values(item, key))
    return values

# 示例JSON数据
json_data = '''
{
    "name": "John",
    "age": 30,
    "address": {
        "city": "New York",
        "name": "Downtown"
    },
    "contacts": [
        {"type": "email", "value": "john@example.com"},
        {"type": "phone", "value": "123-456-7890"},
        {"type": "email", "value": "john.doe@example.com"}
    ]
}
'''

# 解析JSON数据
data = json.loads(json_data)

# 获取所有名为"name"的值
names = get_values(data, 'name')
print(names)  # 输出: ['John', 'Downtown']

import json
from jsonpath_ng import parse

# 示例JSON数据
json_data = '''
{
    "name": "John",
    "age": 30,
    "address": {
        "city": "New York",
        "name": "Downtown"
    },
    "contacts": [
        {"type": "email", "value": "john@example.com"},
        {"type": "phone", "value": "123-456-7890"},
        {"type": "email", "value": "john.doe@example.com"}
    ]
}
'''

# 解析JSON数据
data = json.loads(json_data)

# 使用jsonpath-ng获取所有名为"name"的值
jsonpath_expr = parse('**.name')
names = [match.value for match in jsonpath_expr.find(data)]
print(names)  # 输出: ['John', 'Downtown']