如何比较两个数组并检查js(es6/7)中的值差异？

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];

const set1 = new Set(array1);
const set2 = new Set(array2);

// 找到array1中独有的值
const difference1 = [...array1.filter(x => !set2.has(x))];

// 找到array2中独有的值
const difference2 = [...array2.filter(x => !set1.has(x))];

console.log(difference1); // [1, 2]
console.log(difference2); // [6, 7]

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];

// 找到array1中独有的值
const difference1 = array1.filter(x => !array2.includes(x));

// 找到array2中独有的值
const difference2 = array2.filter(x => !array1.includes(x));

console.log(difference1); // [1, 2]
console.log(difference2); // [6, 7]