如何将列表分配给pandas中的掩码行

import pandas as pd

df = pd.DataFrame({'A': [1, 2, 3, 4, 5],
                   'B': ['a', 'b', 'c', 'd', 'e']})

mask = [False, True, False, True, False]

df.loc[mask, 'A'] = [10, 20]

import pandas as pd

df = pd.DataFrame({'A': [1, 2, 3, 4, 5],
                   'B': ['a', 'b', 'c', 'd', 'e']})

mask = [False, True, False, True, False]
df.loc[mask, 'A'] = [10, 20]

print(df)

   A  B
0  1  a
1  10 b
2  3  c
3  20 d
4  5  e