如何在每个记录的日期范围内显示“每个”月的最新记录

import datetime

# 假设记录存储在一个列表中，每个记录是一个字典，包含日期字段和其他字段
records = [
    {"date": datetime.datetime(2022, 1, 5), "data": "Record 1"},
    {"date": datetime.datetime(2022, 1, 10), "data": "Record 2"},
    {"date": datetime.datetime(2022, 2, 3), "data": "Record 3"},
    {"date": datetime.datetime(2022, 2, 15), "data": "Record 4"},
    {"date": datetime.datetime(2022, 3, 8), "data": "Record 5"},
]

# 确定日期范围
start_date = min(record["date"] for record in records)
end_date = max(record["date"] for record in records)

# 按照月份分组并找到每个月的最新记录
current_date = start_date
while current_date <= end_date:
    month_records = [record for record in records if record["date"].month == current_date.month]
    latest_record = max(month_records, key=lambda record: record["date"])
    
    # 在这里可以根据需求进行展示或者其他操作
    print(f"Month: {current_date.month}, Latest Record: {latest_record}")
    
    current_date = current_date.replace(month=current_date.month+1)