如何在 Hibernate 注释中创建 Tinyint 字段

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name = "example_table")
public class ExampleEntity {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column(name = "tinyint_field", columnDefinition = "TINYINT")
    private Integer tinyintField;

    // getters and setters
}