如何合并两个在同一列表中具有不同键的字典？

def merge_dicts(dict1, dict2):
    merged_dict = dict1.copy()  # 创建一个新字典，初始值为第一个字典的内容

    for key, value in dict2.items():
        if key in merged_dict:
            # 根据具体需求选择合并策略，这里选择覆盖原有值
            merged_dict[key] = value
        else:
            merged_dict[key] = value

    return merged_dict

# 示例用法
dict1 = {"key1": "value1", "key2": "value2"}
dict2 = {"key2": "new_value2", "key3": "value3"}

merged_dict = merge_dicts(dict1, dict2)
print(merged_dict)

{'key1': 'value1', 'key2': 'new_value2', 'key3': 'value3'}