如何使用spring mvc通过Jaxb从Http Post Rest Web Service中解组xml？

@Controller
@RequestMapping("/api")
public class MyController {

    @PostMapping("/xml")
    public ResponseEntity<String> handleXmlRequest(@RequestBody String xmlData) {
        try {
            // 创建JAXB上下文
            JAXBContext jaxbContext = JAXBContext.newInstance(MyObject.class);

            // 创建Unmarshaller
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();

            // 解组XML
            StringReader reader = new StringReader(xmlData);
            MyObject myObject = (MyObject) unmarshaller.unmarshal(reader);

            // 处理解组后的Java对象
            // ...

            return ResponseEntity.ok("XML data processed successfully.");
        } catch (JAXBException e) {
            e.printStackTrace();
            return ResponseEntity.status(HttpStatus.INTERNAL_SERVER_ERROR).body("Failed to process XML data.");
        }
    }
}