如何从spring filter返回Json格式的响应？

import com.fasterxml.jackson.databind.ObjectMapper;

import javax.servlet.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

public class JsonFilter implements Filter {
    private final ObjectMapper objectMapper = new ObjectMapper();

    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
        // 初始化操作，可留空
    }

    @Override
    public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
        HttpServletRequest request = (HttpServletRequest) servletRequest;
        HttpServletResponse response = (HttpServletResponse) servletResponse;

        // 设置响应的Content-Type为application/json
        response.setContentType("application/json");

        // 创建一个包含需要返回的数据的Java对象
        MyDataObject dataObject = new MyDataObject();
        dataObject.setName("John");
        dataObject.setAge(25);

        // 将Java对象转换为JSON格式的字符串
        String json = objectMapper.writeValueAsString(dataObject);

        // 将JSON字符串作为响应的内容写入HttpServletResponse对象中
        response.getWriter().write(json);
    }

    @Override
    public void destroy() {
        // 销毁操作，可留空
    }
}