如何从数组或列表中删除两个元素的序列？

def remove_sequence(lst, a, b):
    i = 0
    while i < len(lst) - 1:
        if lst[i] == a and lst[i + 1] == b:
            del lst[i:i + 2]
        else:
            i += 1
    return lst

# 示例
lst = [1, 2, 3, 4, 5, 2, 3, 6]
result = remove_sequence(lst, 2, 3)
print(result)  # 输出: [1, 4, 5, 6]

function removeSequence(arr, a, b) {
    let i = 0;
    while (i < arr.length - 1) {
        if (arr[i] === a && arr[i + 1] === b) {
            arr.splice(i, 2);
        } else {
            i++;
        }
    }
    return arr;
}

// 示例
let arr = [1, 2, 3, 4, 5, 2, 3, 6];
let result = removeSequence(arr, 2, 3);
console.log(result);  // 输出: [1, 4, 5, 6]

import java.util.ArrayList;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        List<Integer> list = new ArrayList<>();
        list.add(1);
        list.add(2);
        list.add(3);
        list.add(4);
        list.add(5);
        list.add(2);
        list.add(3);
        list.add(6);

        removeSequence(list, 2, 3);
        System.out.println(list);  // 输出: [1, 4, 5, 6]
    }

    public static void removeSequence(List<Integer> list, int a, int b) {
        list.removeIf(x -> x == a && (list.isEmpty() || list.get(list.indexOf(x) + 1) != b));
    }
}