如何从完整url字符串中仅获取路径

from urllib.parse import urlparse

def get_path_from_url(url):
    parsed_url = urlparse(url)
    return parsed_url.path

# 示例
url = "https://www.example.com/path/to/resource?query=param"
path = get_path_from_url(url)
print(path)  # 输出: /path/to/resource

from urllib.parse import urlparse

def get_path_from_url(url):
    try:
        parsed_url = urlparse(url)
        return parsed_url.path
    except ValueError as e:
        print(f"Error parsing URL: {e}")
        return None

# 示例
url = "https://www.example.com/path/to/resource?query=param"
path = get_path_from_url(url)
if path:
    print(path)  # 输出: /path/to/resource
else:
    print("Invalid URL")