基于列表更改特定节点形状

class ListNode:
    def __init__(self, value=0, next=None):
        self.value = value
        self.next = next

def change_node_value(head, index, new_value):
    current = head
    current_index = 0
    
    while current:
        if current_index == index:
            current.value = new_value
            return True
        current = current.next
        current_index += 1
    
    return False

# 示例用法
# 创建一个简单的链表: 1 -> 2 -> 3
head = ListNode(1)
head.next = ListNode(2)
head.next.next = ListNode(3)

# 更改第2个节点的值（索引从0开始）
change_node_value(head, 1, 10)

# 打印链表
current = head
while current:
    print(current.value, end=" -> ")
    current = current.next
print("None")