在Swift中将curl转换为URL请求

import Foundation

guard let url = URL(string: "https://example.com") else {
    print("Invalid URL")
    return
}

var request = URLRequest(url: url)

request.httpMethod = "GET"

request.allHTTPHeaderFields = [
    "Content-Type": "application/json",
    "Authorization": "Bearer token"
]

let bodyData = "key1=value1&key2=value2".data(using: .utf8)
request.httpBody = bodyData

let session = URLSession.shared
let task = session.dataTask(with: request) { (data, response, error) in
    if let error = error {
        print("Error: \(error)")
        return
    }
    
    // 处理响应数据
    if let data = data {
        let responseString = String(data: data, encoding: .utf8)
        print("Response: \(responseString ?? "")")
    }
}
task.resume()