在使用python访问adb shell之后，我想输出子目录和特定目录的所有文件。

import subprocess

# 执行adb shell命令
result = subprocess.run(['adb', 'shell', 'ls', '-R', '/path/to/directory'], capture_output=True, text=True)

# 检查命令执行结果
if result.returncode == 0:
    output = result.stdout
    # 处理输出结果
    # ...
else:
    error = result.stderr
    # 处理错误信息
    # ...

import re

# 提取文件和子目录的信息
file_pattern = re.compile(r'(?<=/path/to/directory/).*')  # 匹配文件路径
directory_pattern = re.compile(r'(?<=/path/to/directory/)[^/]+(?=:?$)')  # 匹配子目录路径

files = file_pattern.findall(output)
directories = directory_pattern.findall(output)

# 输出文件和子目录
print("Files:")
for file in files:
    print(file)

print("Directories:")
for directory in directories:
    print(directory)