删除子列表中位于特定索引处的所有元素- python 2

sub_list = [1, 2, 3, 4, 5]
index_to_remove = 2
# 删除从索引2开始到列表末尾的所有元素
sub_list = sub_list[:index_to_remove]
print(sub_list)  # 输出: [1, 2]

sub_list = [1, 2, 3, 4, 5]
index_to_remove = 2
# 删除索引2处的元素
del sub_list[index_to_remove:]
print(sub_list)  # 输出: [1, 2]

sub_list = [1, 2, 3, 4, 5]
index_to_remove = 2
# 删除索引2及之后的所有元素
sub_list = [item for i, item in enumerate(sub_list) if i < index_to_remove]
print(sub_list)  # 输出: [1, 2]