使用PHP过滤JSON输出

$data = array(
    'name' => 'John',
    'age' => 30,
    'email' => 'john@example.com'
);

$json = json_encode($data, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE);
echo $json;

$data = array(
    'name' => 'John',
    'age' => 30,
    'email' => 'john@example.com'
);

$filteredData = array_filter($data, function($value, $key) {
    // 过滤掉年龄小于等于25岁的数据
    if ($key == 'age' && $value <= 25) {
        return false;
    }
    return true;
}, ARRAY_FILTER_USE_BOTH);

$json = json_encode($filteredData);
echo $json;

$data = array(
    'name' => 'John',
    'age' => 30,
    'email' => 'john@example.com'
);

function filterData($data) {
    // 过滤掉邮箱中包含敏感词的数据
    $data['email'] = preg_replace('/(badword1|badword2)/i', '***', $data['email']);
    return $data;
}

$filteredData = filterData($data);
$json = json_encode($filteredData);
echo $json;