Beautifulsoup中文本搜索的即时标签
Beautifulsoup中文本搜索的即时标签
提问于 2017-02-16 15:06:57
我正在搜索一个特定的字符串，它应该与标签的文本值完全匹配。我如何才能只使用'RESULTS‘这个词进行搜索，并将标签'h4’返回给我？
soup = BeautifulSoup('<table><tbody><tr><td class="fulltext-body-paragraph"><a name="44"></a><div class="fulltext-LEVEL1"><h4>RESULTS</h4></div></td></tr></tbody></table>')
soup.find(lambda el: el.text == 'RESULTS').name
Out: 'html' # I would like it to return 'h4'回答 1
Stack Overflow用户
发布于 2017-02-16 15:45:42
这个(https://stackoverflow.com/a/13349041/7573286)可能会解决你的问题？
from bs4 import BeautifulSoup
from pprint import pprint
import re
html_text = """
<h2>this is cool #12345678901</h2>
<h2>this is nothing</h2>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>
"""
soup = BeautifulSoup(html_text)
# Even though the OP was not looking for 'cool', it's more understandable to work with item zero.
pattern = re.compile(r'cool')
pprint(soup.find(text=pattern).__dict__)
#>> {'next': u'\n',
#>> 'nextSibling': None,
#>> 'parent': <h2>this is cool #12345678901</h2>,
#>> 'previous': <h2>this is cool #12345678901</h2>,
#>> 'previousSibling': None}
print soup.find('h2')
#>> <h2>this is cool #12345678901</h2>
print soup.find('h2', text=pattern)
#>> this is cool #12345678901
print soup.find('h2', text=pattern).parent
#>> <h2>this is cool #12345678901</h2>
print soup.find('h2', text=pattern) == soup.find('h2')
#>> False
print soup.find('h2', text=pattern) == soup.find('h2').text
#>> True
print soup.find('h2', text=pattern).parent == soup.find('h2')
#>> True页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/42267131
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