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社区首页 >问答首页 >Flask返回TypeError:视图函数未返回有效响应

Flask返回TypeError:视图函数未返回有效响应
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Stack Overflow用户
提问于 2019-07-10 04:36:32
回答 2查看 12.6K关注 0票数 0

我是Flask的新手,正在尝试使用flask建立简单的用户表单页面,并遇到错误。当我试图渲染纯超文本标记语言,扩展base.html,一切都很好,但是当添加宏时,结果如下。我试了所有的方法,但我不能自己解决这个问题。任何提示,我做错了什么?

代码语言:javascript
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[2019-07-09 22:19:39,837] ERROR in app: Exception on / [GET]
Traceback (most recent call last):
  File "path/venv/lib/python3.6/site-packages/flask/app.py", line 2446, in wsgi_app
    response = self.full_dispatch_request()
  File "path/venv/lib/python3.6/site-packages/flask/app.py", line 1952, in full_dispatch_request
    return self.finalize_request(rv)
  File "path/venv/lib/python3.6/site-packages/flask/app.py", line 1967, in finalize_request
    response = self.make_response(rv)
  File "path/venv/lib/python3.6/site-packages/flask/app.py", line 2130, in make_response
    " {rv.__class__.__name__}.".format(rv=rv)
TypeError: The view function did not return a valid response. The return type must be a string, dict, tuple, Response instance, or WSGI callable, but it was a UserForm.
127.0.0.1 - - [09/Jul/2019 22:19:39] "GET / HTTP/1.1" 500 -

这是我的Python代码:

代码语言:javascript
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from app import app
from flask import render_template
from flask_wtf import FlaskForm
from wtforms import StringField, TextAreaField, SelectField
from wtforms.validators import InputRequired


@app.route('/', methods=['GET', 'POST'])

class UserForm(FlaskForm):
    prefix = StringField("Prefix", validators=[InputRequired()])
    anrede = StringField("Anrede", validators=[InputRequired()])

def form():
    form = UserForm()
    return render_template('html_one_flask.html', form=form)

我正在尝试加载的表单

代码语言:javascript
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{% extends "base.html" %}

{% from "render_field.html" import render_field %}
{% block content %}

<div class = "container">
    <div class = "spacer" > </div>
</div>
<div class = "container" id = "data_category">PERSONAL DATEN</div>
<div class = "container">
    <div class = "spacer" > </div>
        <div class="form-group row flex-v-center" id = 1>
            {{ render_field(form.prefix), placeholder = form.prefix.label.text }}
            {{ render_field(form.anrede), placeholder = form.anrede.label.text }}
        </div>
</div>
{% endblock %}

和从另一个文件导入的宏

代码语言:javascript
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{% macro render_field(field) %}

<div class = "col-0.75">
    <div class = "spacer_label" > </div>
    <label for="{{ field.name }}">{{ field.label.text }} </label>
</div>
<div class = "col-1">
    {{ field(class_ = "form-control input-sm", **kwargs|safe }}
</div>

{% endmacro %}
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回答 2

Stack Overflow用户

回答已采纳

发布于 2019-07-10 08:43:47

您的@app.route应该位于视图函数之上,而不是类声明之上:

代码语言:javascript
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@app.route('/', methods=['GET', 'POST'])
def form():
    ...
票数 4
EN

Stack Overflow用户

发布于 2019-07-10 17:39:48

你把@app.route装饰者放在了王家

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/56960188

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