为什么我的JavaScript循环没有进入？
为什么我的JavaScript循环没有进入？
提问于 2020-02-04 23:27:32
我有一个JavaScript函数，它迭代从Java方法接收的数据。我可以看到数据变量正在被填充，但是没有进入循环；
JavaScript -在web控制台中，数据变量填充为data=[{"id":"1","name":"Megan","pay":100.0}]，web控制台中显示以下错误；
jquery-3.3.1.js:3963 jQuery.Deferred exception: Cannot use 'in' operator to search for 'length' in [{"id":"1","name":"Megan","pay":100.0}] TypeError: Cannot use 'in' operator to search for 'length' in [{"id":"1","name":"Megan","pay":100.0}]
at isArrayLike (http://localhost:8080/jquery-3.3.1.js:498:33)
at Function.each (http://localhost:8080/jquery-3.3.1.js:359:8)
at Object.<anonymous> (http://localhost:8080/csvTest.js:10:11)
at mightThrow (http://localhost:8080/jquery-3.3.1.js:3665:29)
at process (http://localhost:8080/jquery-3.3.1.js:3741:12) undefined$(document).ready(function() {
$('#test').click(function() {
$.ajax({
url: "/test"
}).then(function(data) {
$.each(data, function (i, item) {
console.log(item.name);
});
});
});
});返回数据的方法；
@GetMapping("/test")
@ResponseBody
public String getEmployeePercentageMatch(HttpServletRequest request, HttpServletResponse response,String roleName, String percentageMatch) throws IOException {
percentageMatch="50";
List<Employee> matchEmployees = new ArrayList<Employee>();
Optional<Role> currentRole=roleRepository.findByroleNameIs("SWEM");
Optional<List<RoleMapSkill>> skillsForRoles = roleMapSkillRepository.getSkillsForRole(currentRole);
List<RoleMapSkill> skillsForRole = skillsForRoles.get();
for(int i=0; i<skillsForRole.size(); i++) {
Map<String, String> roleSkillMap = new HashMap<String, String>();
roleSkillMap.put(skillsForRoles.get().get(i).getIdSkill().getIdSkill(), skillsForRoles.get().get(i).getRating());
System.out.println(skillsForRoles.get().get(i).getIdSkill().getIdSkill()+" "+roleSkillMap.get(skillsForRoles.get().get(i).getIdSkill().getIdSkill()));
}
List<Employee> allEmployees = employeeRepository.findAll();
for(int i=0; i<allEmployees.size(); i++) {
int totalPercentage=0;
Employee currentEmployee = allEmployees.get(i);
Optional<List<EmployeeMapSkill>> skillEmployeeMap = employeeMapSkillRepository.getSkillsForEmployee(currentEmployee);
for(int j=0; j<skillsForRole.size(); j++) {
if(skillEmployeeMap.isPresent()){
Map<String,String> employeeSkillMap = new HashMap<String, String>();
employeeSkillMap.put(skillEmployeeMap.get().get(j).getIdSkill().getIdSkill(), skillEmployeeMap.get().get(j).getRating());
}
}
for(int k=0; k<skillsForRole.size(); k++) {
if(skillEmployeeMap.isPresent()){
int individualPercentageMatch=(100/Integer.valueOf(skillsForRoles.get().get(k).getRating()))*Integer.valueOf(skillEmployeeMap.get().get(k).getRating());
totalPercentage= totalPercentage+individualPercentageMatch;
}
}
int totalPercentageMatch = totalPercentage/skillsForRole.size();
System.out.println(totalPercentageMatch);
if(totalPercentageMatch>=Integer.valueOf(percentageMatch)) {
matchEmployees.add(currentEmployee);
}
}
String json = new Gson().toJson(matchEmployees);
PrintWriter writer = response.getWriter();
writer.write(json);
return null;
}回答 1
Stack Overflow用户
发布于 2020-02-04 23:36:52
这就是JQuery；我不喜欢这样，但是(在所有人的帮助下)……缺少dataType: 'json'
关于你的代码
$('#test').click(function() {
$.ajax({
url: "/test",
dataType: 'json'
}).then(function(data) {
$.each(data, function (i, item) {
console.log(item.name);
});
});
});但是我不是很确定..。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/60060594
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