重新排序文件中每一行的文本，并最终转换为XML。
重新排序文件中每一行的文本，并最终转换为XML。
提问于 2014-11-07 16:57:45
我正在处理一个日志文件，我需要重新排序每一行(而不是排序)。日志文件如下所示：
11-06-2014 - 10:49:06PM lat = 41.858657; lon = -91.345142
11-06-2014 - 10:49:49PM lat = 42.864653; lon = -92.349914
11-06-2014 - 10:50:35PM lat = 43.874808; lon = -93.350364
11-06-2014 - 10:51:21PM lat = 44.885047; lon = -94.350058
11-06-2014 - 10:52:08PM lat = 45.895078; lon = -95.349920
11-06-2014 - 10:53:30PM lat = 46.905178; lon = -96.349837
11-06-2014 - 10:54:50PM lat = 47.910303; lon = -97.350606我想把日期/时间移到每一行的末尾：
lat = 41.858657; lon = -91.345142 11-06-2014 - 10:49:06PM
lat = 42.864653; lon = -92.349914 11-06-2014 - 10:49:49PM
lat = 43.874808; lon = -93.350364 11-06-2014 - 10:50:35PM
lat = 44.885047; lon = -94.350058 11-06-2014 - 10:51:21PM
lat = 45.895078; lon = -95.349920 11-06-2014 - 10:52:08PM
lat = 46.905178; lon = -96.349837 11-06-2014 - 10:53:30PM
lat = 47.910303; lon = -97.350606 11-06-2014 - 10:54:50PMsed？awk？多么?
额外的问题:我的最终目标是将其转换为gpx/xml，添加中间文本可能与处理每一行一样容易，因此out看起来如下所示：
<wpt lat="41.858657" lon="-91.345142">
<time>11-06-2014 - 10:49:06PM</time>
</wpt>
<wpt lat"="42.864653" lon="-92.349914">
<time>11-06-2014 - 10:49:49PM</time>
</wpt>
<wpt lat"="43.874808" lon="-93.350364">
<time>11-06-2014 - 10:50:35PM</time>
</wpt>
<wpt lat"="44.885047" lon="-94.350058">
<time>11-06-2014 - 10:51:21PM</time>
</wpt>
<wpt lat"="45.895078" lon="-95.349920">
<time>11-06-2014 - 10:52:08PM</time>
</wpt>
<wpt lat"="46.905178" lon="-96.349837">
<time>11-06-2014 - 10:53:30PM</time>
</wpt>
<wpt lat"="47.910303" lon="-97.350606">
<time>11-06-2014 - 10:54:50PM</time>
</wpt>回答 2
Unix & Linux用户
发布于 2014-11-07 21:05:04
sed ' s/ *[=;]"* */="/g;s//" /2 #first sub-out spaces; for "
s|\(.*M\) \(.*\)|\ #then do the replace
<wpt \2">\
<time>\1</time>\
</wpt>|
' <<\INPUT
11-06-2014 - 10:49:06PM lat = 41.858657; lon = -91.345142
11-06-2014 - 10:49:49PM lat = 42.864653; lon = -92.349914
11-06-2014 - 10:50:35PM lat = 43.874808; lon = -93.350364
11-06-2014 - 10:51:21PM lat = 44.885047; lon = -94.350058
11-06-2014 - 10:52:08PM lat = 45.895078; lon = -95.349920
11-06-2014 - 10:53:30PM lat = 46.905178; lon = -96.349837
11-06-2014 - 10:54:50PM lat = 47.910303; lon = -97.350606
INPUT这就是我想出来的。它在sed中相当简单。我在这里使用文字字符是因为我读起来更容易，而且并不是所有的sed's都会在右手替换字段中处理反斜杠转义。如果是这样，那就放心吧。无论如何，那些内联注释肯定会弄脏任何sed，所以在测试之前一定要删除它们。
输出
<wpt lat="41.858657" lon="-91.345142">
<time>11-06-2014 - 10:49:06PM</time>
</wpt>
<wpt lat="42.864653" lon="-92.349914">
<time>11-06-2014 - 10:49:49PM</time>
</wpt>
<wpt lat="43.874808" lon="-93.350364">
<time>11-06-2014 - 10:50:35PM</time>
</wpt>
<wpt lat="44.885047" lon="-94.350058">
<time>11-06-2014 - 10:51:21PM</time>
</wpt>
<wpt lat="45.895078" lon="-95.349920">
<time>11-06-2014 - 10:52:08PM</time>
</wpt>
<wpt lat="46.905178" lon="-96.349837">
<time>11-06-2014 - 10:53:30PM</time>
</wpt>
<wpt lat="47.910303" lon="-97.350606">
<time>11-06-2014 - 10:54:50PM</time>
</wpt>Unix & Linux用户
发布于 2021-07-16 03:56:38
使用Raku的
(以前称为Perl_6):
$ raku -e 'my @reordered = do for lines() {(.words[3..*],.words[0..2])}; .put for @reordered;' input.txt
lat = 41.858657; lon = -91.345142 11-06-2014 - 10:49:06PM
lat = 42.864653; lon = -92.349914 11-06-2014 - 10:49:49PM
lat = 43.874808; lon = -93.350364 11-06-2014 - 10:50:35PM
lat = 44.885047; lon = -94.350058 11-06-2014 - 10:51:21PM
lat = 45.895078; lon = -95.349920 11-06-2014 - 10:52:08PM
lat = 46.905178; lon = -96.349837 11-06-2014 - 10:53:30PM
lat = 47.910303; lon = -97.350606 11-06-2014 - 10:54:50PM.还是致力于XML-输出解决方案.。
页面原文内容由Unix & Linux提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://unix.stackexchange.com/questions/166675
复制相关文章
相似问题
腾讯云开发者
