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社区首页 >问答首页 >使用javascript对表格进行排序

使用javascript对表格进行排序
EN

Stack Overflow用户
提问于 2021-09-16 08:56:46
回答 2查看 63关注 0票数 2

我有一个简单的HTML表格,如下所示:

代码语言:javascript
运行
复制
    <table id="myTable">
<thead>
  <tr>
    <th class="pointer" onClick="sortTable()">Number</th>
    <th>Example3</th>
    <th>Example2</th>
    <th>Example1</th>
  </tr>
</thead>
<tbody>
  <tr>
    <td>101</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-01</td>
  </tr>
  <tr>
    <td>102</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-02</td>
  </tr>
</tbody>
  
</table>

和用于在javascript中对该表进行排序的函数,但它不起作用。我想按列号对表进行降序排序。如何解决这个问题?我还想通过单击箭头在要调用函数的列名旁边添加一个箭头

代码语言:javascript
运行
复制
function sortTable() {
  var table, rows, switching, i, x, y, shouldSwitch;
  table = document.getElementById("myTable");
  switching = true;
  /*Make a loop that will continue until
  no switching has been done:*/
  while (switching) {
    //start by saying: no switching is done:
    switching = false;
    rows = table.rows;
    /*Loop through all table rows (except the
    first, which contains table headers):*/
    for (i = 1; i < (rows.length - 1); i++) {
      //start by saying there should be no switching:
      shouldSwitch = false;
      /*Get the two elements you want to compare,
      one from current row and one from the next:*/
      x = rows[i].getElementsByTagName("TD")[0];
      y = rows[i + 3].getElementsByTagName("TD")[0];
      //check if the two rows should switch place:
      if (Number(x.innerHTML) > Number(y.innerHTML)) {
        //if so, mark as a switch and break the loop:
        shouldSwitch = true;
        break;
      }
    }
    if (shouldSwitch) {
      /*If a switch has been marked, make the switch
      and mark that a switch has been done:*/
      rows[i].parentNode.insertBefore(rows[i + 3], rows[i]);
      switching = true;
    }
  }
}
EN

回答 2

Stack Overflow用户

发布于 2021-09-16 09:11:10

如果你多读一下你所在的页面(https://www.w3schools.com/howto/howto_js_sort_table.asp),你就会找到这个问题的答案。

代码语言:javascript
运行
复制
function sortTable(n) {
  var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
  table = document.getElementById("myTable");
  switching = true;
  // Set the sorting direction to ascending:
  dir = "asc";
  /* Make a loop that will continue until
  no switching has been done: */
  while (switching) {
    // Start by saying: no switching is done:
    switching = false;
    rows = table.rows;
    /* Loop through all table rows (except the
    first, which contains table headers): */
    for (i = 1; i < (rows.length - 1); i++) {
      // Start by saying there should be no switching:
      shouldSwitch = false;
      /* Get the two elements you want to compare,
      one from current row and one from the next: */
      x = rows[i].getElementsByTagName("TD")[n];
      y = rows[i + 1].getElementsByTagName("TD")[n];
      /* Check if the two rows should switch place,
      based on the direction, asc or desc: */
      if (dir == "asc") {
        if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) {
          // If so, mark as a switch and break the loop:
          shouldSwitch = true;
          break;
        }
      } else if (dir == "desc") {
        if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) {
          // If so, mark as a switch and break the loop:
          shouldSwitch = true;
          break;
        }
      }
    }
    if (shouldSwitch) {
      /* If a switch has been marked, make the switch
      and mark that a switch has been done: */
      rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
      switching = true;
      // Each time a switch is done, increase this count by 1:
      switchcount ++;
    } else {
      /* If no switching has been done AND the direction is "asc",
      set the direction to "desc" and run the while loop again. */
      if (switchcount == 0 && dir == "asc") {
        dir = "desc";
        switching = true;
      }
    }
  }
}
代码语言:javascript
运行
复制
    <table id="myTable">
<thead>
  <tr>
    <th class="pointer" onClick="sortTable(0)">Number</th>
    <th>Example3</th>
    <th>Example2</th>
    <th>Example1</th>
  </tr>
</thead>
<tbody>
  <tr>
    <td>101</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-01</td>
  </tr>
  <tr>
    <td>102</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-02</td>
  </tr>
</tbody>
  
</table>

在这里关联小提琴:https://jsfiddle.net/Louf0sc7/

票数 0
EN

Stack Overflow用户

发布于 2021-09-16 09:14:11

为什么使用rowsi +3而不是rowsi + 1进行切换?为什么要打破循环,直到结束才继续呢?

代码语言:javascript
运行
复制
function sortTable() {
  var table, rows, switching, x, y;
  table = document.getElementById("myTable");
  /*Make a loop that will continue until
  no switching has been done:*/
  do {
    //start by saying: no switching is done:
    switching = false;
    rows = table.rows;
    /*Loop through all table rows (except the
    first, which contains table headers):*/
    for (var i = 1; i < (rows.length - 1); i++) {
      //start by saying there should be no switching:
      /*Get the two elements you want to compare,
      one from current row and one from the next:*/
      x = rows[i].getElementsByTagName("TD")[0];
      y = rows[i + 1].getElementsByTagName("TD")[0];
      //check if the two rows should switch place:
      if (Number(x.innerHTML) > Number(y.innerHTML)) {
        //if so, mark as a switch
        switching = true;
        rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
        rows = table.rows;
      }
    }
    // run until no switches
  } while (switching)
}
代码语言:javascript
运行
复制
<table id="myTable">
<thead>
  <tr>
    <th class="pointer" onClick="sortTable()">Number</th>
    <th>Example3</th>
    <th>Example2</th>
    <th>Example1</th>
  </tr>
</thead>
<tbody>
  <tr>
    <td>101</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-01</td>
  </tr>
  <tr>
    <td>102</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-02</td>
  </tr>
  <tr>
    <td>100</td>
    <td>TOM</td>
    <td>Not Working</td>
    <td>AUTOMAT-00</td>
  </tr>
</tbody>
  
</table>

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/69205335

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