我有一个Firebase管理助手类,我正在用Spock进行测试。如果需要,该类的构造函数将调用类中的另一个方法来初始化某些字段,如下所示:
public class FirebaseUtility {
private static FirebaseDatabase db = null;
public FirebaseUtility() throws IOException {
if (db == null) {
initializeFirebase();
}
}
public void initializeFirebase() throws IOException {
InputStream serviceAccount = ClassLoader.getSystemResourceAsStream("serviceAccount.json");
FirebaseOptions options = new FirebaseOptions.Builder()
.setCredentials(GoogleCredentials.fromStream(serviceAccount))
.setDatabaseUrl("<my_database_url>").build();
FirebaseApp.initializeApp(options);
db = FirebaseDatabase.getInstance();
}
}基本上,如果已经设置了FirebaseDatabase,那么执行所有初始化代码是没有意义的。
我试过这样做,但似乎行不通:
class FirebaseUtilitySpec extends Specification {
def "instantiating FirebaseUtility should run initialization code"() {
given:
def f
when:
f = new FirebaseUtility()
then:
1 * f.initializeFirebase()
}
}发布于 2018-06-16 07:58:25
首先,您不能检查原始对象上的交互,您需要使用模拟或间谍。此外,这些类型的对象不能拦截静态方法或构造函数上的交互。为此,您必须将Mockito,甚至PowerMock添加到混合中。但是基本上,静态方法是丑陋的,在构造函数调用中初始化静态成员是不必要的。只需为数据库对象使用懒散的getter并拦截其行为即可。
我已经稍微简化了您的示例,消除了外部依赖,只是模拟了Firebase,这样就可以更容易地使用MCVE来回答
package de.scrum_master.stackoverflow;
public class FirebaseDatabase {
private static FirebaseDatabase instance;
public static FirebaseDatabase getInstance() {
if (instance == null)
instance = new FirebaseDatabase();
return instance;
}
}package de.scrum_master.stackoverflow;
public class FirebaseUtility {
private static FirebaseDatabase db = null;
public FirebaseDatabase getDb() {
if (db == null)
initializeFirebase();
return db;
}
protected void initializeFirebase() {
db = FirebaseDatabase.getInstance();
}
}package de.scrum_master.stackoverflow
import spock.lang.Specification
class FirebaseUtilitySpec extends Specification {
def "instantiating FirebaseUtility runs initialization code exactly once"() {
given:
FirebaseUtility f = Spy()
when:
f.getDb()
then:
1 * f.initializeFirebase()
when:
f.getDb()
then:
0 * f.initializeFirebase()
}
}https://stackoverflow.com/questions/50885121
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