我有两个大约80个数据的列表-一个用于节点,另一个用于边缘。我想使用single函数graph_from_dataframe来连接节点和边缘,dataframes生成一个igraph的列表。目前我一直在尝试这样做:
glst <- mapply(graph_from_data_frame,
d=ListOfEdgeDfs,
vertices=ListOfNodeDfs,
SIMPLIFY = FALSE,
directed =F)
但是,这会给出错误消息:
Error in (function (d, directed = TRUE, vertices = NULL) :
Some vertex names in edge list are not listed in vertex data frame
有人知道我该怎么做吗?
发布于 2017-01-18 10:34:53
以下工作(对于2个图的列表,对于任意数量的图都应该是相同的,您能确保数据框架结构是相似的吗):
ListOfEdgeDfs <- list(data.frame(from=letters[1:3], to=c('b', 'c', 'd')),
data.frame(from=rep('a',3), to=c('b', 'c', 'd')))
ListOfEdgeDfs
#[[1]]
# from to
#1 a b
#2 b c
#3 c d
#[[2]]
# from to
#1 a b
#2 a c
#3 a d
ListOfNodeDfs <- list(data.frame(node=letters[1:4]), data.frame(node=letters[1:4]))
ListOfNodeDfs
#[[1]]
# node
#1 a
#2 b
#3 c
#4 d
#[[2]]
# node
#1 a
#2 b
#3 c
#4 d
library(igraph)
glst <- mapply(graph_from_data_frame,
d=ListOfEdgeDfs,
vertices=ListOfNodeDfs,
SIMPLIFY = FALSE,
directed =F)
par(mfrow=c(1,2))
#plot(glst[[1]])
#plot(glst[[2]])
编辑的
试试这个:
n <- 2 # number of graphs
par(mfrow=c(2,1)) # if you have 100 graphs, try par(mfrow=c(10,10)) e.g.
invisible(sapply(1:n, function(i) plot(glst[[i]], vertex.size=50)))
https://stackoverflow.com/questions/41725684
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