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社区首页 >问答首页 >按日期和总和分组-日期格式和顺序

按日期和总和分组-日期格式和顺序
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Stack Overflow用户
提问于 2015-06-14 13:21:11
回答 1查看 48关注 0票数 4

我在试着得到一天销售量的总和。我需要在日期之前把结果整理好。下面的查询给出了我需要的确切结果,除了日期没有格式化为我所需要的。

代码语言:javascript
复制
SELECT  CAST(Datetime AS DATE) AS 'date', SUM(quantity) as total_quantity
FROM Invoice_Itemized ii
INNER JOIN Invoice_Totals it ON it.Invoice_Number = ii.Invoice_Number
WHERE ii.ItemNum = '4011'
AND it.datetime > '05/15/2015'
GROUP BY CAST(Datetime AS DATE)

SELECT DATENAME(MM, datetime) + ' ' + CAST(DAY(datetime) AS VARCHAR(2)) AS [DD Month], SUM(quantity) as total_quantity
FROM Invoice_Itemized ii
INNER JOIN Invoice_Totals it ON it.Invoice_Number = ii.Invoice_Number
WHERE ii.ItemNum = '4011'
AND it.datetime > '05/15/2015'
GROUP BY DATENAME(MM, datetime) + ' ' + CAST(DAY(datetime) AS VARCHAR(2))

顶部查询的结果:

  1. 2015-05-15 91.43
  2. 2015-05-16 84.77

底部查询的结果:

  1. 128.34年月一日
  2. 6月10日85.06

顶部的查询按我需要的顺序给出了我需要的信息。下面的查询给出了我需要的日期格式,但顺序不对。

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2015-06-14 13:27:42

如果确实需要应用不同的格式,可以使用派生表:

代码语言:javascript
复制
select 
    DATENAME(MM, [date]) + ' ' + CAST(DAY([date]) AS VARCHAR(2)) AS [DD Month], 
    total_quantity 
from 
(
    SELECT  CAST([Datetime] AS DATE) AS [date], SUM(quantity) as total_quantity
    FROM Invoice_Itemized ii
    INNER JOIN Invoice_Totals it ON it.Invoice_Number = ii.Invoice_Number
    WHERE ii.ItemNum = '4011'
    AND it.[datetime] > '05/15/2015'
    GROUP BY CAST(Datetime AS DATE)
) as X

通过这种方式,您可以将结果包装到派生表中,然后对其应用其余的操作。

我想这也是可行的,但现在不能测试:

代码语言:javascript
复制
SELECT  DATENAME(MM, CAST([datetime] AS DATE)) + ' ' 
+ CAST(DAY(CAST([datetime] AS DATE)) AS VARCHAR(2)) AS [DD Month], 
SUM(quantity) as total_quantity
FROM Invoice_Itemized ii
INNER JOIN Invoice_Totals it ON it.Invoice_Number = ii.Invoice_Number
WHERE ii.ItemNum = '4011'
AND it.[datetime] > '05/15/2015'
GROUP BY CAST([datetime] AS DATE)
票数 3
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/30829875

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