问将值从jquery传递给Cakephp控制器

EN

<?php
echo $this->Form->textarea('text_box',array(
    'id' => 'my_text',
));
?>
<div id="ajax_output"></div>

function process_ajax(){
        var post_url = '<?php echo $this->Html->url(array('controller' => 'users', 'action' => 'ajax_process')); ?>';

        var text_box_value = $('#my_text').val();

        $.ajax({
            type : 'POST',
            url : post_url,
            data: {
                text : text_box_value
            },
            dataType : 'html',
            async: true,
            beforeSend:function(){
                $('#ajax_output').html('sending');
            },
            success : function(data){
                $('#ajax_output').html(data);
            },
            error : function() {
                $('#ajax_output').html('<p class="error">Ajax error</p>');
            }
        });
    }

public function ajax_process(){
    $this->autoRender = false; //as not to render the layout and view - you dont have to do this
    $data = $this->request->data; //the posted data will come as $data['text']
    pr($data); //Debugging - print to see the data - this value will be sent back as html to <div id="ajax_output"></div>
}

public function beforeFilter() {
    $this->Security->unlockedActions = array('ajax_process');
}