将元素动态添加到XML文件中
将元素动态添加到XML文件中
提问于 2014-12-15 10:50:28
目前，我正在使用以下代码创建一个XML文件，其中创建一个对象，该对象每次调用该方法时都会写入XML文件：
public static void TileMapCapabilities(string title, TilePicker picker)
{
var dbInfo = picker.GetCapabilitiesInfo();
TileMapObject tmo = new TileMapObject()
{
Title = title,
Abstract = "",
KeywordList = new KeywordList() {FirstLayer = ""},
SRS = "OSGEO:41001",
Profile = "local",
Format = "image/png",
BoundingBox = dbInfo.eBoundingBox,
MapSize = dbInfo.mapSize,
CellSize = dbInfo.cellSize,
MaxLevel = dbInfo.level,
Location = dbInfo.location // Not sure if this should be here. Could be practical in scenarios where the tile server is hosted locally.
};}它运行得很好，看起来可能是这样的：
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>kraken.db</Title>
<href>10.10.100.200/kraken.db?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>现在，我要做的是创建一个XML文件，它可以描述上面提到的层。换句话说，我想要一个XML文件，对上面的每个XML文件都有一个简短的描述。
我已经完成了一些工作，如果我在值中编写硬代码，它将如下所示：
public static void TileMapServicesCapabilities(int listBoxCount)
{
TileMapServicesObject tmso = new TileMapServicesObject()
{
TileMapService = new TileMapService()
{
Title = "EivaTMS",
Abstract = "Something clever about this service",
TileMaps = new List<TileMap>
{
new TileMap { Title = "title1", href = "http://title1/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"},
new TileMap { Title = "title2", href = "http://title2/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"},
new TileMap { Title = "title3", href = "http://title3/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"}
}
}
};}它产生这个输出：
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>title1</Title>
<href>http://title1/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title2</Title>
<href>http://title2/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title3</Title>
<href>http://title3/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>现在，我要做的是动态地创建和添加元素。这意味着，对于第一个方法TileMapCapabilities创建的每个XML文件，我都希望创建一个对象并将其添加到TileMapServicesObject中。还应该提到类的外观，这些类包含正在创建的对象中的信息：
public class TileMapServicesObject
{
public TileMapService TileMapService { get; set; }
}
public class TileMapService
{
public string Title { get; set; }
public string Abstract { get; set; }
public List<TileMap> TileMaps { get; set; }
}
public class TileMap
{
public string Title { get; set; }
public string href { get; set; }
public string Profile { get; set; }
public string SRS { get; set; }
}我一直在尝试使用foreach循环为我要添加到服务中的每个TileMap创建一个TileMap对象，但是这只是为每次迭代创建了一个新的TileMapServicesObject，而不是包含所有对象的单个文件。
对我如何处理这个问题有什么提示吗？如果我的要求在目前的形式上过于含糊，请告诉我。
编辑:原来只是盯着它足够长的时间固定它！
以下是更新的代码：
public static void TileMapServicesCapabilities()
{
TileMapServicesObject tmso = new TileMapServicesObject();
List<string> pathList = new List<string>();
pathList = Directory.GetFiles(path + @"Tilemaps\").ToList();
List<TileMap> tmList = new List<TileMap>();
TileMap tm = new TileMap();
string title = "";
string profile = "";
string srs = "";
foreach (var p in pathList)
{
var xRead = XDocument.Load(p);
var xd = (from el in xRead.Descendants("TileMapObject")
select new
{
Title = el.Element("Title").Value,
Profile = el.Element("Profile").Value,
SRS = el.Element("SRS").Value
}).SingleOrDefault();
title = xd.Title;
profile = xd.Profile;
srs = xd.SRS;
tm = new TileMap()
{
Title = title,
Profile = profile,
SRS = srs,
href = "http://10.10.100.200/" + title + "?request=getcapabilities"
};
tmList.Add(tm);
}
tmso = new TileMapServicesObject()
{
TileMapService = new TileMapService()
{
Title = "EivaTMS",
Abstract = "Something clever about this service",
TileMaps = tmList
}
};它给了我这个漂亮的XML文件：
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>title1</Title>
<href>http://title1?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title2</Title>
<href>http://title2?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title3</Title>
<href>http://title3?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title4</Title>
<href>http://title4?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>回答 1
Stack Overflow用户
回答已采纳
发布于 2014-12-15 14:29:21
好吧，经过几个小时的盯着它，我终于修好了这个！
结果，我可以做一个foreach()，在这里迭代我想要读取的所有文件，创建一个TileMap对象并将它添加到一个列表中，然后在foreach()之后将它写到XML中。我用我的新代码更新了OP。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/27482374
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