java通信vlc的缓冲问题
java通信vlc的缓冲问题
提问于 2013-09-10 23:32:35
我是一个新手对套接字沟通，所以我可能是错误的，但请建议或至少给出方向！
我正在根据http://www.csee.umbc.edu/~pmundur/courses/CMSC691C/lab5-kurose-ross.html#appendix实现RTSP服务器，查看来自http://www.java2s.com/Open-Source/Android/UnTagged/mynpr/com/webeclubbin/mynpr/RTSPserver.java.htm的类似代码
目前，我正在实现对选项请求的响应。为了简化第一种方法，我决定根据为vlc和gstreamer之间的实际通信所做的rtsp请求/响应日志示例对答案进行硬编码。
因此，用vlc -vvv记录的日志上写着：
Sending request: OPTIONS rtsp://localhost:8554/test RTSP/1.0
CSeq: 2
User-Agent: LibVLC/2.0.8 (LIVE555 Streaming Media v2013.04.30)
Received 183 new bytes of response data.
Received a complete OPTIONS response:
RTSP/1.0 200 OK
CSeq: 2
Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN
Server: GStreamer RTSP server
Date: Tue, 10 Sep 2013 19:56:53 GMT
Sending request: DESCRIBE rtsp://localhost:8554/test RTSP/1.0
CSeq: 3
User-Agent: LibVLC/2.0.8 (LIVE555 Streaming Media v2013.04.30)
Accept: application/sdp即
RTSP/1.0 200 OK
CSeq: 2
Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN
Server: GStreamer RTSP server
Date: Tue, 10 Sep 2013 19:56:53 GMT部分有183个字节长。
我正在根据这个例子写信给缓冲区：
try{
System.out.println("S -> C");
System.out.println("RTSP/1.0 200 OK");
System.out.println("CSeq: "+RTSPSeqNb);
//System.out.println("Session: "+RTSP_ID);
if (responceType==OPTIONS) {System.out.println("Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN");};
if (responceType==OPTIONS) {System.out.println("Server: GStreamer RTSP server"); };
if (responceType==OPTIONS) {System.out.println("Date: Tue, 10 Sep 2013 19:56:53 GMT");};
RTSPBufferedWriter.write("RTSP/1.0 200 OK"+CRLF);
RTSPBufferedWriter.write("CSeq: "+RTSPSeqNb+CRLF);
//RTSPBufferedWriter.write("Session: "+RTSP_ID+CRLF);
if (responceType==OPTIONS) {RTSPBufferedWriter.write("Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN"+CRLF);};
if (responceType==OPTIONS) {RTSPBufferedWriter.write("Server: GStreamer RTSP server"+CRLF); };
if (responceType==OPTIONS) {RTSPBufferedWriter.write("Date: Tue, 10 Sep 2013 19:56:53 GMT"+CRLF); };
RTSPBufferedWriter.write("Session: "+RTSP_ID+"\r"+CRLF);
RTSPBufferedWriter.flush();
//RTSPBufferedWriter.newLine();
System.out.println("RTSP Server - Sent response to Client.");
}
catch(IOException ex)
{
System.out.println("Exception caught: "+ex.getStackTrace());
// System.exit(0);
}vlc日志上写着
Opening connection to 127.0.0.1, port 6666...
...remote connection opened
Sending request: OPTIONS rtsp://127.0.0.1:6666/autostream.mjpg RTSP/1.0
CSeq: 2
User-Agent: LibVLC/2.0.8 (LIVE555 Streaming Media v2013.04.30)
Received 193 new bytes of response data.
[0x7fd01c001178] live555 demux debug: connection timeout
[0x7fd01c001178] live555 demux error: Failed to connect with rtsp://127.0.0.1:6666/autostream.mjpg在那里“\n”。在我尝试CRLF="\r\n“(最后一行中没有+"\r"+ )之前
Received 198 new bytes of response data.那么，那里有什么问题？vlc还在等什么？为什么这个例子中的默认参数不适用于它？
回答 1
Stack Overflow用户
回答已采纳
发布于 2013-09-10 23:41:28
我好像总是在我把问题发布到堆栈溢出后找到答案.
双CRLF应该站在通常RTSP协议的最后一个标头之后，而不是在示例中使用的定制报头之后)。
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原文链接：
https://stackoverflow.com/questions/18730383
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