我有一个测试代码:
#include <time.h>
#include <stdio.h>
#include <chrono>
namespace chrono = std::chrono;
int main()
{
struct timespec ts;
clock_gettime(CLOCK_REALTIME, &ts);
printf("time %ld.%09ld\n", ts.tv_sec, ts.tv_nsec);
chrono::time_point<chrono::high_resolution_clock> t(chrono::seconds(ts.tv_sec));
t += chrono::nanoseconds(ts.tv_nsec);
chrono::seconds secs = chrono::duration_cast<chrono::seconds>(t.time_since_epoch());
chrono::nanoseconds nsecs = chrono::duration_cast<chrono::nanoseconds>(t.time_since_epoch() - secs);
printf("time %ld.%09ld\n", secs.count(), nsecs.count());
}它在带有g++ 4.7.3的Ubuntu上编译得很好,但是在一个4.7.2的Debian 7框上,我得到了这个编译输出:
/home/atip/chronotest.cpp: In function ‘int main()’:
/home/atip/chronotest.cpp:15:40: error: no match for ‘operator+=’ in ‘t += std::chrono::duration<long int, std::ratio<1l, 1000000000l> >((*(const long int*)(& ts.timespec::tv_nsec)))’
/home/atip/chronotest.cpp:15:40: note: candidate is:
In file included from /home/atip/chronotest.cpp:3:0:
/usr/include/c++/4.7/chrono:550:2: note: std::chrono::time_point<_Clock, _Dur>& std::chrono::time_point<_Clock, _Dur>::operator+=(const duration&) [with _Clock = std::chrono::system_clock; _Dur = std::chrono::duration<long int, std::ratio<1l, 1000000l> >; std::chrono::time_point<_Clock, _Dur> = std::chrono::time_point<std::chrono::system_clock, std::chrono::duration<long int, std::ratio<1l, 1000000l> > >; std::chrono::time_point<_Clock, _Dur>::duration = std::chrono::duration<long int, std::ratio<1l, 1000000l> >]
/usr/include/c++/4.7/chrono:550:2: note: no known conversion for argument 1 from ‘std::chrono::nanoseconds {aka std::chrono::duration<long int, std::ratio<1l, 1000000000l> >}’ to ‘const duration& {aka const std::chrono::duration<long int, std::ratio<1l, 1000000l> >&}’不知道该怎么破译,我怎么才能做到这两样东西呢?最终,我有一个函数,它得到一个timespec,我想把它转换成一个chrono::time_point,然后再把它转换回来。
发布于 2013-08-17 01:02:39
假设这两种实现是一致的。
显然,在Ubuntu上,high_resolution_clock的分辨率是nanoseconds或更精细,但在Debian 7上,high_resolution_clock的分辨率要比nanoseconds高。编译时错误防止您意外地截断算法:
t += chrono::nanoseconds(ts.tv_nsec);nanoseconds不能被准确地表示出来。
如果需要,可以通过特别请求截断来解决这一问题:
t += chrono::duration_cast<chrono::high_resolution_clock::duration>(chrono::nanoseconds(ts.tv_nsec));这将截断为零。或者,您可以选择其他舍入模式,尽管您需要自己实现它们。这里是一个用于chrono::duration (搜索“圆形”)的整数到偶数算法的例子。
https://stackoverflow.com/questions/18284045
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